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call ulab.numerical.std directly in timeit

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```
Computing the RMS value of 100 numbers
traditional          :    5.188ms [result=3535.843611]
ulab, with ndarray, some implementation in python :    0.504ms [result=3535.853624]
ulab only, with list :    0.636ms [result=3535.854340]
ulab only, with ndarray :    0.121ms [result=3535.854340]
```
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Zoltán Vörös 2020-05-02 14:18:15 +02:00 committed by GitHub
parent 734497f951
commit d012c336b2
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1 changed files with 2 additions and 5 deletions
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7
ulab_Crunch_Numbers_Fast/benchmark.py
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@ -21,9 +21,6 @@ def normalized_rms_ulab(values):
values = values - minbuf
samples_sum = ulab.numerical.sum(values * values)
return math.sqrt(samples_sum / len(values))
def normalized_std_ulab(values):
return ulab.numerical.std(values)
# Instead of using sensor data, we generate some data
# The amplitude is 5000 so the rms should be around 5000/1.414 = 3536
@ -41,5 +38,5 @@ def timeit(s, f, n=100):
print("Computing the RMS value of 100 numbers")
timeit("traditional", lambda: normalized_rms(nums_list))
timeit("ulab, with ndarray, some implementation in python", lambda: normalized_rms_ulab(nums_array))
timeit("ulab only, with list", lambda: normalized_std_ulab(nums_list))
timeit("ulab only, with ndarray", lambda: normalized_std_ulab(nums_array))
timeit("ulab only, with list", lambda: ulab.numerical.std(nums_list))
timeit("ulab only, with ndarray", lambda: ulab.numerical.std(nums_array))