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announce version of the current API by means of FUSE_PYTHON_API_VERSION constant

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dzsekijo 2006-10-14 20:48:04 +00:00
parent 4ca78fbdad
commit caffe5fd92
2 changed files with 8 additions and 5 deletions
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9
README.new_fusepy_api
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@ -313,7 +313,8 @@ safely passed down to FUSE.
Long-term compatibility
-----------------------
You are suggested to declare explicitly that you use the current API by setting
``fuse.fuse_python_api = (0, 2)``. This ensures that your code will keep
working even if further API revisions take place. (At the moment this setting
will make no difference.)
You are suggested to declare explicitly the API you use by setting
``fuse.fuse_python_api`` to the value of ``fuse.FUSE_PYTHON_API_VERSION`` as
it's definied in the fuse.py instance you code your filesystem against. This
ensures that your code will keep working even if further API revisions take
place.

4
fuse.py
View file

@ -37,7 +37,8 @@ from fuseparts.setcompatwrap import set
###
##########
# The actual API version of this module
FUSE_PYTHON_API_VERSION = (0, 2)
def __getenv__(var, pattern = '.', trans = lambda x: x):
"""
@ -67,6 +68,7 @@ def get_fuse_python_api():
def get_compat_0_1():
return get_fuse_python_api() == (0, 1)
# API version to be used
fuse_python_api = __getenv__('FUSE_PYTHON_API', '^[\d.]+$',
lambda x: tuple([int(i) for i in x.split('.')]))